Suppose a steam locomotive is rated at 7500 horsepower. if its efficiency is 6%, how much wood must be burned in a 3-hour trip? 1 hp = 750 w. wood has an energy density of 20.0 mj/ kg.

50,625kg of wood

Explanation:

Power input = power output ÷ efficiency

Power output = 7500 horsepower = 7500×750W = 5625000W, efficiency = 6% = 0.06

Power input = 5625000/0.06 = 93750000W

Energy input = power input × time

time = 3hour = 3×3600 = 10800sec

Energy input = 93750000 × 10800 = 1.0125×10^12J

Mass = Energy ÷ Energy density = (1.0125×10^12J) ÷ (20×10^6J/kg) = 50,625kg of wood

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )