The velocity potential for a certain inviscid, incompressible flow field is given by the equation:
φ = 2x^y - (2/3) y^3
where φ has the units of m^2/s when x and y are in meters. determine the pressure at the point x = 2.3 m, y = 2.3 m if the pressure at x = 1 m, y = 1 m is 1900 kpa. elevation changes can be neglected, and the fluid is water.

answer:

look in settings

explanation:

answer:

i cant give me a pic

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)