Given a dictionary d and a list lst, remove all elements from the dictionary whose key is an element of lst. for example, given the dictionary {1: 2, 3: 4, 5: 6, 7: 8} and the list [1, 7], the resulting dictionary would be {3: 4, 5: 6}. assume every element of the list is a key in the dictionary.

d = {1:2, 3:4, 5:6, 7:8}

list = [1, 7]

not_found = set()

for x in list:

  if x not in d.keys():

     not_found.add(x)

  else:

     del d[x]

print(d)

print(not_found)

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

glad i could , give me a follow, so if you need with any other question, im here.