Engineering, 13.11.2019 18:31, mandy9386

Adigital computer has a memory unit with 32 bits per word. the instruction set consists of 128 different operations. all instructions have an operation code part (opcode) and two address fields: one for a memory address and one for a register address. this particular system includes eight general-purpose, user-addressable registers. registers may be loaded directly from memory, and memory may be updated directly from the registers. direct memory-to-memory data movement operations are not supported. each instruction stored in one word of memory.
a) how many bits are needed for the opcode?
7 bits are needed for opcode
b) how many bits are needed to specify the register?
32-7/4 = 6 bits
c) how many bits are left for the memory address part of the instruction?
25-6 =19 bits
d) what is the maximum allowable size for memory?
e) what is the largest unsigned binary number that can be accommodated in one word of memory?
i think i have a, b, & c. i need with d & e. (also if you see and errors in a-c, note)

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Adigital computer has a memory unit with 32 bits per word. the instruction set consists of 128 diffe...