Radioactive wastes are temporarily stored in a spherical container, the center of which is buried a distance of 10 m below the earth’s air-soil surface. the outside diameter of the container is 2.2 m, and 500 w of heat are released as a result of radioactive decay. if the soil surface temperature is 15°c, what is the outside surface temperature of the container?

76.3 ° C

Explanation:

Outside Distance = 10 m

Outside diameter, d = 2.2 m

R=D/2 = 2.2/2= 1.1 m

inner radius, Rs = = 1.1 m

Surface Temperature Ts = 20°C

Given that the thermal conductivity of soil, K = 0.52 W/mK

We can find the outside temperature of the container by finding the thermal temperature of conductor, T, and then summing up with the surface temperature

That is (T + Ts)

we know amount of heat, Q is given by :

Q = [(T-Ts) / (R- Rs)/4πKRRs

500 = T-20 [4π×0.52×1.1×10] / (10-1.1)

500= T-20 (71.88/8.9)

500 = T-20 (8.08)

500 = 8.08T - 161.6

8.08T = 500 + 161.6

8.08T = 661.6

T = 76.33 ° C

can you make it more obvious. i can't see it properly

answer:

the answer is d

explanation: