An irrigation district is being formed to provide water to 5000 acres of cropland. the estimated average evapotranspiration (et) for the crop is 24" for the growing season. the average precipitation for the same period is 11". the soil has a water holding capacity of 0.1" of water per inch of soil. the root zone is three feet deep, and the soil moisture is maintained at half its water holding capacity. also, the soil profile is saturated to its field capacity at the beginning of the season, which corresponds to the bottom of the root zone (i. e., 3’ below the surface). assume that the irrigation system is properly managed (i. e., no surface runoff (q=0) or groundwater recharge (g = what is the volume of irrigation water required for a growing season?

answer:

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explanation:

answer:

gwcfcsgscx

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)

 They're compact and can easily be used for both FWD and RWD vehicles. Allows for greater displacement than inline cylinder engines, typically meaning more power.