Acentrifugal blower delivers 6m^3 of air per second against a head of 55mm of alcohol of relative density 0.79 when running at 400 rpm. calculate the power required if the efficiency os 0.7. estimate the discharge of a blower of similar design of twice the diameter when discharging against a head of 55mm of alcohol. calculate the operating speed and the expected power. air density is 1.17kg/m^3

speed is 200 rpm

power is 14614.1 W

Explanation:

given data

discharge Q = 6 m³

head H = 55 mm

running s =  400 rpm

relative density R = 0.790 Kg/m³

efficiency e = 0.7

Air Density = 1.17 Kg/m³

to find out

speed and the expected power

solution

we will apply here 1s power formula that is

power = Q × R × g× H / e    1

put here all value

power = 6 × 790 × 9.8 × 0.055 / 0.7

power = 3653.52 W

and we know discharge is directly proportional to square of diameter

so

Q1/Q2 = D1²/D2²    2

here we know blower design twice the diameter so D2 is 2D

6/Q2 = D²/(2D)²

so Q2 = 24 m³/s

so speed is

D1 × S = D2 × S1

D × 400 = 2D × S1

S1 = 200

speed is 200 rpm

and

power is

P1/P2 = Q1/Q2

3653.52 / P2 = 6 / 24

P2 = 14614.1

so power is 14614.1 W

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