Asolid 0.75 in diameter steel shaft transmits 7 hp at 3,200 rpm. determine the maximum shear stress magnitude produced in the shaft. hint: use p=tω and convert hp to ft-lbf/s. find τ by using tc/j. recall max shear stress will be on the outer most surface.

=11.468MPa

Explanation:

Given data

=7 hp=5220 W

N=3200rpm

==335.14 rad/s

diameter=0.75in=19.05mm

we know

P=

5220=

T=15.57 N-m

And

=

=

=

=11.468MPa

Maximum shear stress is 11.47 MPa.

Explanation:

Given:

D=.75 in⇒D=19.05 mm

P=7 hp⇒ P=5219.9 W

N=3200 rpm

We know that

    P=T

Where T is the torque and is the speed of shaft.

   P=

So    5219.9=

 T=15.57 N-m

We know that maximum shear stress in shaft

=11.47 MPa

So maximum shear stress is 11.47 MPa.

answer:

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explanation:

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