0.50 kg of air is heated at constant pressure from 25°c to 100°c. the source of the heat is at 200°c. what is the entropy generation for the process?

Solution:

Given:

mass of air, m = 0.50 Kg

= 25°C = 273+25 = 298 K

= 100°C = 273+100 = 373 K

= 200°C = 273+100 = 473 K

Solution:

Formulae used:

ΔQ = mCΔT                                          (1)

ΔS =    (2)

where,

ΔQ = change in heat transfer

ΔS = chane in entropy

C = specific heat

ΔT = change in system temperature

Using eqn (1)

ΔQ = = 36.687 kJ

Now, for entropy generation, using eqn (2)

ΔS = = 0.0796 kJ

answer:

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explanation: