How many possibilities or states are there in binary code?

Write a function processpeople() that takes the name of a file as a parameter. each line of the file corresponds to information about a person. in particular a line contains either a name (in the form lastname, firstname with no spaces in it) or a name (lastname, firstname) and a year. the function will process the file, creating a person object for each line in the file. the function will print information about each line as it processes it, as well as appending the new person object into a list. make sure to use person methods to display information rather than recreating the work you did for the first problem. once the entire file has been processed, the function returns the list of person objects created from the file. if the file is empty, the function should return an empty list. if the input file cannot be opened, the function should print a message to that effect and then return an empty list. the following shows what would be displayed for two example files which have been provided in the link. the file none. txt does not exist. note that your function must work on an arbitrary file that consists of valid lines. you cannot assume anything about the file except that it contains lines that have the format described above.

Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }

Write a method that takes in an array of point2d objects, and then analyzes the dataset to find points that are close together. be sure to review the point2d api. in your method, if the distance between any pair of points is less than 10, display the distance and the (x, y)s of each point. for example, "the distance between (3,5) and (8,9) is 6.40312." the complete api for the point2d adt may be viewed at ~pf/sedgewick-wayne/algs4/documenta tion/point2d. html (links to an external site.)links to an external site.. try to write your program directly from the api - do not review the adt's source code.