Computers and Technology
Computers and Technology, 31.01.2022 05:30, tystar84

HELP!!! For this assignment, you will create a calendar program that allows the user
to enter a day, month, and year in three separate variables as shown below.
Day:
Month:
Year:
Then, your program should ask the user to select from a menu of choices
using this formatting
Menu:
1) Calculate the number of days in the given month.
2) calculate the number of days left in the given year.

Your program must include the three following functions:
leap_year
number_of_days
days_left

Parameters:
leap_year(y)
number_of_days(m, y)
days_left(d, m, y)

This is the code I have so far but I'm still getting some errors:
def leap_year(y):#defining a method leap_year that takes one parameter

l= 0#defining l variable that holds an integer

if y % 4 == 0:#using if block that check year value module by 4 equal to 0

l = 1#holding value in l variable

if y % 100 == 0:#using if block that check year value module by 100 equal to 0

l = 0#holding value in l variable

if y % 400 == 0:#using if block that check year value module by 400 equal to 0

l= 1#holding value in l variable

return l#return l value

def number_of_days(m, y):#defining a method number_of_days that takes two parameters

months = {1: 31, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31}#defining months variable that hold value in ictionary

l = leap_year(y)#defining l variable that calls leap_year method and holds its value

if l == 1 and m == 2:#use if that check l value equal to 1 and 2

return 29#return value 29

if m == 2:#use if that check month value equal to 2

return 28#return value 29

return months[m]#return months value

def days_left(d, m, y):#defining a method days_left that takes three variable in parameter

l = leap_year(y)#defining l variable that hold leap_year method value

days = 0#defining days variable that hold integer value

months = {1: 31, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31}#defining months variable that hold value in ictionary

if l== 1:#using if that check l equal to 1

if m > 2:#defining if that check m value greater than 2

days += (29 + 31)#using days variable that Calculate holds its value

i = m#defining i variable that holds months value

while i > 2:#defining while loop that checks other days

days += months[i]#defining a days variable that holds months value

i -= 1#decreasing i value

days -= (months[m] - d)#defining days that subtracts leap value

elif m == 2:#defining elif block that checks m equal to 2

days += (29 - d) + 31#holding value in days variable

else:#defining else block

days = 31 - d#Calculating days value

return 366 - days#using return keyword that Calculates days value

else:#defining else block

if m > 2:#using if that checks m value greater than 2

days += (28 + 31)#Calculating and store value in days

i = m#holding months value in i

while i > 2:#defining while loop that checks i value greater than 2

days += months[i]#holding list value in days

i -= 1#decreasing i value

days -= (months[m] - d)#defining days that subtracts leap value

elif m == 2:#using elif block that checks m value equal to 2

days += (28 - d) + 31#Calculating and store value in days

else:#defining else block

days = 31 - d##Calculating and store value in days

return 365 - days#return total days

print("Please enter a date")#print message

day = int(input("Day: "))#input value

month = int(input("Month: "))#input value

year = int(input("Year: "))#input value

print("Menu: ")#print message

print("1) Calculate the number of days in the given month.")#print message

print("2) Calculate the number of days left in the given year.")#print message

c = int(input())#input value

if c == 1:#using if that checks c value equal to 1

print(number_of_days(month, year))#calling method and print its return value

elif c == 2:#using if that checks c value equal to 2

print(days_left(day, month, year))#calling method and print its return value

can someone please help me out? I will mark whoever gives me the right code the brainliest!!!

answer
Answers: 1

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