Computers and Technology, 14.12.2021 18:40, liljett

What is stringconstant?

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Computers and Technology, 22.06.2019 11:00, Yamari000

What are two of the most common reasons that peolpe who need mental health care do not access it?

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Computers and Technology, 22.06.2019 13:50, juan3937

The instruction ishl (shift left integer) exists in jvm but not in ijvm. it uses the top two values on the stack, replacing the two with a single value, the result. the sec- ond-from-top word of the stack is the operand to be shifted. its content is shifted left by a value between 0 and 31, inclusive, depending on the value of the 5 least signifi- cant bits of the top word on the stack (the other 27 bits of the top word are ignored). zeros are shifted in from the right for as many bits as the shift count. the opcode for ishl is 120 (0x78).a. what is the arithmetic operation equivalent to shifting left with a count of 2? b. extend the microcode to include this instruction as a part of ijv.

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Computers and Technology, 23.06.2019 15:00, billlyyyyyyyyyy

Visually impaired individuals generally rely on the for navigation. thus, designers need to ensure that mouse-specific inputs, such as pointing, clicking, and hovering, can be done without a mouse.

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Computers and Technology, 23.06.2019 17:30, Annlee23

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?