Computers and Technology

Write 10 place where computer use and it uses

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Computers and Technology, 22.06.2019 04:30, fatherbamboo
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Computers and Technology, 22.06.2019 21:00, jarrettashlyn
Write a method so that the main() code below can be replaced by the simpler code that calls method original main(): public class calcmiles { public static void main(string [] args) { double milesperhour; double minutestraveled; double hourstraveled; double milestraveled; milesprhour = scnr. nextdouble(); minutestraveled = scnr. nextdouble(); hourstraveled = minutestraveled / 60.0; milestraveled = hourstraveled * milesperhour; system. out. println("miles: " + milestraveled); } }
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Computers and Technology, 23.06.2019 16:50, lukeakalucas
15: 28read the summary of "an indian's view of indian affairs."15 betterin "an indian's view of indian affairs," it is asserted that conflicts could be reduced if white americansunderstood native americans..pswhich of the following would make this summary more complete? eleo the fact that chief joseph believes the great spirit sees everythinthe fact that chief joseph was born in oregon and is thirty-eight years oldo the fact that chief joseph states that he speaks from the hearthehehethe fact that chief joseph of the nez percé tribe made this claimebell- ==feetle===-felsefe ==submitmark this and retum.=
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Computers and Technology, 23.06.2019 17:30, Annlee23
When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?
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