Computers and Technology, 25.11.2021 05:30, itsgiovanna
In our analysis of the select algorithm for a block size of 5, we compared the median of the medians with every other element in the input array to partition it. However, that led to more comparisons than we should have done. We could reduce it since we know that at least 3n/10 elements are less than or equal to the median of the medians and similar number of elements is at least greater than or equal to the median of the medians. Obtain a new upper bound on the worst-case number of comparisons using this piece of information. What is the value of the constant?
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In our analysis of the select algorithm for a block size of 5, we compared the median of the medians...
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