Computers and Technology

The step-by-step procedure to solve any problem is called an

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Computers and Technology, 22.06.2019 22:00, zay179
What is a distinguishing feature of today’s graphic application software?) graphic applications are used today on a variety of devices, including touch-screen kiosks and mobile phones.
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Computers and Technology, 22.06.2019 23:30, Nason156
What are some ways to use a range name in a formula? check all that apply. in the defined names group, click use in formula, and then select the desired name. begin typing the name in the formula, select a name from the autocomplete list, and use the arrow keys and tab key to enter the name in the formula. begin typing the formula, and then click and drag with the mouse to select the cells to include in the formula. right-click one of the cells in the range. click formula options, and use the dialog box to add the name.
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Computers and Technology, 23.06.2019 02:00, deeknuk
What is the main benefit of minimizing the ribbon in word? more options will be accessible through customized keystrokes. more of the document will be viewable without needing to scroll. fewer controls will be accessible to the user by using the mouse. fewer editing options will be available without entering a password.
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Computers and Technology, 23.06.2019 17:30, Annlee23
When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2Δƒβ€”, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5Δƒβ€” slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?
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