Array Challenge Have the function ArrayChallenge (arr) take the array of numbers stored in arr and return the string true if any two numbers can be multiplied so that the answer is greater than double the sum of all the elements in the array. If not, return the string false. For example: if arr is (2, 5, 6, -6, 16, 2, 3, 6, 5, 3] then the sum of all these elements is 42 and doubling it is 84. There are two elements in the array, 16 * 6 = 96 and 96 is greater than 84, so your program should return the string true. Examples Input: [2, 2, 2, 2, 4, 11 Output: false Input: 11, 1.2, 10, , 1, 121 Outputt true

The code is given as follows,

Explanation:

Code:

#include <stdio.h>

#include <string.h>  

int n; //to store size of array  

char* ArrayChallenge(int arr[]) //function returns string true or false

{

  int i, j;

  int sum = 0;

  for(i = 0; i < n; i++)

  {

      sum = sum + arr[i]; //count sum

  }  

  for(i = 0; i < n; i++)

  {

      for(j = i+1; j < n; j++) //loop for every two elements in array

      {

          if(arr[i]*arr[j] > 2*sum) //check if proudct of two elements > 2 times sum

          {

              printf("\n%d x %d = %d, 2xSum = %d\n", arr[i], arr[j], arr[i]*arr[j], 2*sum);

              return "true"; //If proudct of two elements > 2 times sum. return true

          }

      }

  }

  return "false"; // If proudct of two elements < 2 times sum. return false

}  

int main()

{  

  printf("\nEnter size of array: ");

  scanf("%d", &n); //read size of array

  int A[n]; //array of size n

  printf("\nEnter array elements: ");

  int i;

  for(i = 0; i < n; i++)

  {

      scanf("%d", &A[i]); //read array from stdin

  }

  printf("%s\n",ArrayChallenge(A)); //ccall function and print answer

  return 0;

}

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