Add the following UNSIGNED, byte-sized (8 bits) numbers

10010011
01101110

1 0  0  0  0  0  0   0   1

An overflow occurs if the result is stored in an 8-bit memory.

The actual result will be

0  0  0  0  0  0   0   1

  1   0  0  1   0  0   1   1

+ 0   1   1  0   1   1    1   0

1  0  0  0  0  0  0   0   1

Steps:

i. Arrange the numbers such that the most significant bits and least significant bits of each number are directly positioned one above the other.

ii. Add bitwise starting from the rightmost bit.

Result:

The result from adding these two numbers is

1 0  0  0  0  0  0   0   1

This is a 9-bit number, that means there is an overflow since the addition is done with 8 bits numbers and likely stored in an 8-bit storage. The leftmost bit (which is underlined above) is the overflow bit. Therefore the actual result will be

0  0  0  0  0  0   0   1

i don't know to be honest but you on your own

step-by-step explanation:

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explanation:

i don't know to be honest but you on your own

step-by-step explanation:

ignitia made me retarted fool im stoopid laugh like shi