Computers and Technology, 24.05.2021 21:30, tilsendt

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Computers and Technology, 22.06.2019 20:00, Jana1517

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i. e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }

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continue

Computers and Technology, 23.06.2019 01:50, jumoke26

Create a class named majors that includes an enumeration for the six majors offered by a college as follows: acc, chem, cis, eng, his, phys. display the enumeration values for the user, then prompt the user to enter a major. display the college division in which the major falls. acc and cis are in the business division, chem and phys are in the science division, and eng and his are in the humanities division. save the file as majors. java.

Answers: 2

continue

Computers and Technology, 23.06.2019 16:00, cravens511peeelg

An english teacher would like to divide 8 boys and 10 girls into groups, each with the same combination of boys and girls and nobody left out. what is the greatest number of groups that can be formed?

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continue

Computers and Technology, 24.06.2019 14:40, drecooks713

Create a function (prob3_6) that will do the following: input a positive scalar integer x. if x is odd, multiply it by 3 and add 1. if the given x is even, divide it by 2. repeat this rule on the new value until you get 1, if ever. your program will output how many operations it had to perform to get to 1 and the largest number along the way. for example, start with the number 3: because 3 is odd, we multiply by 3 and add 1 giving us 10. 10 is even so we divide it by 2, giving us 5. 5 is odd so we multiply by 3 and add one, giving us 16. we divide 16 (even) by two giving 8. we divide 8 (even) by two giving 4. we divide 4 (even) by two giving 2. we divide 2 (even) by 2 to give us 1. once we have one, we stop. this example took seven operations to get to one. the largest number we had along the way was 16. every value of n that anyone has ever checked eventually leads to 1, but it is an open mathematical problem (known as the collatz conjectureopens in new tab) whether every value of n eventually leads to 1. your program should include a while loop and an if-statement.

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continue

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