A run is a sequence of adjacent repeated values. Write a program that generates a sequence of 50 random die tosses in
an array and prints the die values, making the runs by including
them in parentheses, like this:

1 2 (5 5) 3 1 2 4 3 (2 2 2 2) 3 6 (5 5) 6 3 1

Add a method alternatingSum() that returns the sum of the
alternating elements in the array and subtracts the others. For
example, if your array contains:

1 4 9 16 9 7 4 9 11
Then the method should compute:

1-4+9-16+9-7+4-9+11 = -2

I am having trouble with this code can someone please help me?

You have inserted new slides based on a word outline. how do you format these new slides to match the powerpoint presentation formatting? a. select all slides in the presentation and click format on the home tab. b. select the new slides and click reset on the home tab. c. select all slides in the presentation and click reset on the home tab. d. select the new slides and click format on the home tab.

What is a point-in-time measurement of system performance?

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }