Computers and Technology, 04.05.2021 02:00, gibbss80stu
Your friend is writing a program that will allow the user to input a year and then print “LEAP!” if that year is a leap year or print “not a leap year” if it is not. However, the program isn’t working properly, and your friend asked you for help in debugging.
Before you take a look at the program, you should know these rules for leap years:
A year is a leap year if it can be divided by 400 without a remainder.
A year is a leap year if it can be divided by 4 without a remainder, unless it can also be divided by 100 without a remainder; if that is the case, it is not a leap year.
All other years are not leap years.
Here is your friend’s code:
year=int(input()
if year%400=0:
print("LEAP!")
else:
print(not a leap year")
elseif year%4==0 and year%100!=0
print(“not a leap year")
Answers: 1
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