1. In the space below, explain how the Table Tools can be accessed in Word.

Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". any value that is the same as the immediately preceding value is considered a consecutive duplicate. in this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. note that the last 3 is not a consecutive duplicate because it was preceded by a 7. write some code that uses a loop to read such a sequence of non-negative integers , terminated by a negative number. when the code finishes executing, the number of consecutive duplicates encountered is printed. in this case, 3 would be printed. assume the availability of a variable, stdin, that references a scanner object associated with standard input. that is, stdin = new scanner(system. in); is given.

Solve the following javafx application: write a javafx application that analyzes a word. the user would type the word in a text field, and the application provides three buttons for the following: - one button, when clicked, displays the length of the word.- another button, when clicked, displays the number of vowels in the word.- another button, when clicked, displays the number of uppercase letters in the word(use the gridpane or hbox and vbox to organize the gui controls).

Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }