Computers and Technology

SELECT vendor_state, vendor_city, vendor_name, COUNT(*) AS invoice_qty, SUM(invoice_total) AS invoice_average FROM invoices JOIN vendors ON invoices. vendor_id = vendors. vendor_id WHERE vendor_state < 'e' GROUP BY vendor_state, vendor_city, vendor_name HAVING SUM(invoice_total) > 500 ORDER BY vendor_state, vendor_city, vendor_name (Please refer to code example above.) When this summary query is executed, the result set will contain one summary row for Answer a. each city with invoice average over $500
b. each vendor with invoice totals over $500 c. each city with invoice totals over $500

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SELECT vendor_state, vendor_city, vendor_name, COUNT(*) AS invoice_qty, SUM(invoice_total) AS invoic...

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