Computers and Technology

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Computers and Technology, 23.06.2019 15:20, manarhizam12
An ou structure in your domain has one ou per department, and all the computer and user accounts are in their respective ous. you have configured several gpos defining computer and user policies and linked the gpos to the domain. a group of managers in the marketing department need different policies that differ from those of the rest of the marketing department users and computers, but you don't want to change the top-level ou structure. which of the following gpo processing features are you most likely to use? a, block inheritance b, gpo enforcement c, wmi filtering d, loopback processing
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Computers and Technology, 23.06.2019 15:30, jasssp
Write a program in plp assembly that counts up by one starting from zero (or one) inside a loop and writes this value to the leds every time the value is increased. the memory address of the leds is 0xf0200000. the table below shows the meaning and an example usage of the instructions covered in the video, plp instructions for project 1. instruction example usage meaning load immediate li $t0, 8 register $t0 is set to the value, 8. store word sw $t2, 0($t1) the value in register $t1 is used as the memory address. the value in register $t2 is copied into this memory address. add addiu $t4, $t3, 29 register $t4 is assigned the sum of 29 and the value in register $t3. jump j your_label_name the program jumps to the line following the label, "your_label_name: ". label your label name: defines a label called "your_label_name: " that can be jumped to
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Computers and Technology, 23.06.2019 22:30, reaganphelps3
What would be the address of the cell, which is at the intersection of the second row and the third column in a worksheet?
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Computers and Technology, 24.06.2019 00:50, anthonycraig0205
3. what is the output of the following statements? temporary object1; temporary object2("rectangle", 8.5, 5); temporary object3("circle", 6, 0); temporary object4("cylinder", 6, 3.5); cout < < fixed < < showpoint < < setprecision(2); object1.print(); object2.print(); object3.print(); object4.print(); object1.set("sphere", 4.5, 0); object1.print();
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