Computers and Technology

What is the name for a list of links you ve visited within a website?

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Computers and Technology, 22.06.2019 05:20, ashcormu11
Write a program called assignment3 (saved in a file assignment3.java) that computes the greatest common divisor of two given integers. one of the oldest numerical algorithms was described by the greek mathematician, euclid, in 300 b. c. it is a simple but very e↵ective algorithm that computes the greatest common divisor of two given integers. for instance, given integers 24 and 18, the greatest common divisor is 6, because 6 is the largest integer that divides evenly into both 24 and 18. we will denote the greatest common divisor of x and y as gcd(x, y). the algorithm is based on the clever idea that the gcd(x, y) = gcd(x ! y, y) if x > = y and gcd(x, y) = gcd(x, y ! x) if x < y. the algorithm consists of a series of steps (loop iterations) where the “larger” integer is replaced by the di↵erence of the larger and smaller integer. this continues until the two values are equal. that is then the gcd.
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Computers and Technology, 23.06.2019 01:30, solikhalifeoy3j1r
In deadlock avoidance using banker’s algorithm, what would be the consequence(s) of: (i) a process declaring its maximum need as maximum possible for each resource. in other words, if a resource a has 5 instances, then each process declares its maximum need as 5. (ii) a process declaring its minimum needs as maximum needs. for example, a process may need 2-5 instances of resource a. but it declares its maximum need as 2.
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Computers and Technology, 23.06.2019 12:40, melaniem50
Curriculum exam to process a resident's payment, you must click on onesite payments home page. from the a. reports b. my settings o c. transactions o d. rent tab
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Computers and Technology, 24.06.2019 00:50, anthonycraig0205
3. what is the output of the following statements? temporary object1; temporary object2("rectangle", 8.5, 5); temporary object3("circle", 6, 0); temporary object4("cylinder", 6, 3.5); cout < < fixed < < showpoint < < setprecision(2); object1.print(); object2.print(); object3.print(); object4.print(); object1.set("sphere", 4.5, 0); object1.print();
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