Computers and Technology

What protocol is used to provide a common language between virtualized service applications and a network's physical devices?

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Computers and Technology, 22.06.2019 10:10, joanasprinkman2262
3. bob is arguing that if you use output feedback (ofb) mode twice in a row to encrypt a long message, m, using the same key each time, it will be more secure. explain why bob is wrong, no matter what encryption algorithm he is using for block encryption (15 points).
Answers: 3
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Computers and Technology, 22.06.2019 23:30, lexirandall19
Define a function printfeetinchshort, with int parameters numfeet and numinches, that prints using ' and " shorthand. ex: printfeetinchshort(5, 8) prints: 5' 8"
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Computers and Technology, 23.06.2019 01:20, sosick90501
Write a function balancechemical to balance chemical reactions by solving a linear set of equations. the inputs arguments are: reagents: symbols of reagents in string row array products: symbols of products in string row array elements: elements in the reaction in string row array elcmpreag: elemental composition of reactants in two dimensional numeric array elcmpprdcts: elemental composition of prducts in two dimensional numeric array hint: the first part of the problem is setting up the set of linear equations that should be solve. the second part of the problem is to find the integers from the solution. one way to do this is to mulitiply the rational basis for the nullspace by increasing larger integers until both the left-and right-side integers exist. for example, for the reaction that involves reacting with to produce and : reagents=["ch4", "o2"]; products =["co2", "h2o"]; elements =["c","h", "o"] elcmpreag=[1,4,0;
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Computers and Technology, 24.06.2019 00:40, sierravick123owr441
Use a software program or a graphing utility with matrix capabilities to solve the system of linear equations using an inverse matrix. x1 + 2x2 βˆ’ x3 + 3x4 βˆ’ x5 = 6 x1 βˆ’ 3x2 + x3 + 2x4 βˆ’ x5 = βˆ’6 2x1 + x2 + x3 βˆ’ 3x4 + x5 = 3 x1 βˆ’ x2 + 2x3 + x4 βˆ’ x5 = βˆ’3 2x1 + x2 βˆ’ x3 + 2x4 + x5 = 5
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