Has anyone else been not showing the “Ad” part to skip? Can anyone help me?

3. (6 pts) internally in the computer, with few exceptions, all numerical computation is done using binary numbers. output, however, often uses ascii, which is formed by appending 011 to the left of a bcd code. thus, an algorithm that directly converts a binary integer to a bcd integer is very useful. here is one such algorithm 1) draw lines to the left of the binary number to bound the expected bcd decades. (each decade is a group of 4 bits.) move the binary number one bit to the left. add 0011 to each bcd decade containing a binary value> 0100 repeat steps 2-3 until the last bit in the binary number has been moved into the least significant decade position. (note that when the last bit has been shifted into bcd decade, step 3 is not repeated.) read the bcd result. 2) 3) 4) 5) a) execute the algorithm for the binary number 1101101 b) execute the algorithm for the binary number 01110101110 4. (4 pts) represent the decimal number 3568 in bcd; excess-3 code; ascil; and hex.

Write a full class definition for a class named player , and containing the following members: a data member name of type string .a data member score of type int .a member function called setname that accepts a parameter and assigns it to name . the function returns no value. a member function called setscore that accepts a parameter and assigns it to score . the function returns no value. a member function called getname that accepts no parameters and returns the value of name .a member function called getscore that accepts no parameters and returns the value of score .this is what i have, aparently this is wrong: class player{private: string name; int score; public: void player: : setname (string n){name =n; }void player: : setscore (int s){score = s; }string player: : getname (){return name; }int player: : getscore (){return score; }};

Does anybody know how to hack into a google account? i had important information on it and it is gone now and i need getting it back.