Write a program that would determine the day number in a non-leap year. For example, in a non-leap year, the day number for Dec 31 is 365; for Jan 1 is 1, and for February 1 is 32. This program will ask the user to input day and month values. Then it will display the day number day number corresponding to the day and month values entered assuming a non-leap year. (See part II to this exercise below).

In Python:

months = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]

daymonths = [31,28,31,30,31,30,31,31,30,31,30,31]

day = int(input("Day: "))

month = input("Month: ")

ind = months.index(month)

numday = 0

for i in range(ind):

   numday+=daymonths[i]

numday+=day

print(numday)    

Explanation:

This initializes the months to a list

months = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]

This initializes the corresponding days of each month to a list

daymonths = [31,28,31,30,31,30,31,31,30,31,30,31]

This gets the day from the user

day = int(input("Day: "))

This gets the month from the user

month = input("Month: ")

This gets the index of the month entered by the user

ind = months.index(month)

This initializes the sum of days to 0

numday = 0

This adds up the days of the months before the month entered by the user

for i in range(ind):

   numday+=daymonths[i]

This adds the day number to the sum of the months

numday+=day

This prints  the required number of days

print(numday)    

Note that: Error checking is not done in this program

the formula for work is

f*d

therefore work=2.0n*3.0=6n*m

its true for the one time