This question is based on the efficient, in-place, divide&conquer-based procedure for building a heap. (7 pts) Using the following array of integers, illustrate the building of a Min-heap (draw the tree) using the divide-and-conquer procedure: 70, 80, 90, 100, 60, 50, 40
(Inefficient procedures like sorting or a greedy/incremental one will score 0 points! )
(2 pts) Identify the recurrence relationship for its time-complexity T(n)
(3 pts) Now, solve the recurrence relationship to identify its time-complexity.

Formula that contains a nested function that first calculates the average of the values in range e6: p6 and uses the round function to round that average to the nearest 10 dollars. use -1 for the value of the number digit argument. would the formula be =round(average(e6: p6),0

1. before plugging in a new device to a computer you should unplug all other devices turn off the computer turn on the computer 2. many of the maintenance tools for a computer can be found in the control panel under administrative tools display personalization

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i. e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }