7.2 need help plzs 15 points

We as humans write math expression in infix notation, e. g. 5 + 2 (the operators are written in-between the operands). in a computer’s language, however, it is preferred to have the operators on the right side of the operands, i. e. 5 2 +. for more complex expressions that include parenthesis and multiple operators, a compiler has to convert the expression into postfix first and then evaluate the resulting postfix. write a program that takes an “infix” expression as input, uses stacks to convert it into postfix expression, and finally evaluates it. it must support the following operations: + - / * ^ % (example infix expression: (7 - 3) / (2 + 2)postfix expression: 7 3 - 2 2 + /result: 1guidelines: 1. you will need to use stacks in three placesa. one for the parenthesis check [char stack]b. one during infix to postfix [char stack]c. one during evaluation [int stack]for a and b above, you can use same array and same push, pop method as both ofthem are char. but for evaluation you have int stack and you might consider to createanother push pop method to handle it. maybe push_int, pop_int, etc. or find otherstrategy to utilize existing push pop method2. you can create a function for obtaining operator priority. that function should take anoperator as input and return its priority as an integer. this function will you a lot andreduce repeated code3. during evaluation you will need to convert char into integer. example for single digit: char c = '5'; int x = c - '0';

In deadlock avoidance using banker’s algorithm, what would be the consequence(s) of: (i) a process declaring its maximum need as maximum possible for each resource. in other words, if a resource a has 5 instances, then each process declares its maximum need as 5. (ii) a process declaring its minimum needs as maximum needs. for example, a process may need 2-5 instances of resource a. but it declares its maximum need as 2.

Write a program in plp assembly that counts up by one starting from zero (or one) inside a loop and writes this value to the leds every time the value is increased. the memory address of the leds is 0xf0200000. the table below shows the meaning and an example usage of the instructions covered in the video, plp instructions for project 1. instruction example usage meaning load immediate li $t0, 8 register $t0 is set to the value, 8. store word sw $t2, 0($t1) the value in register $t1 is used as the memory address. the value in register $t2 is copied into this memory address. add addiu $t4, $t3, 29 register $t4 is assigned the sum of 29 and the value in register $t3. jump j your_label_name the program jumps to the line following the label, "your_label_name: ". label your label name: defines a label called "your_label_name: " that can be jumped to