What is the value stored at x, given the statements: int x;
x=3/(int)(4.5+6.4)

a. 0.3
b. 0
c. .275229
d. 3.3
e. None of these

0.

Explanation:

Given

int x;

x=3/(int)(4.5+6.4)

Required

What is x?

The first line of the code segment declares x as integer. This means that, it will only hold non decimal numbers.

With the above explanation, options (a), (c) and (d) can not be true.

Solving further:

x=3/(int)(4.5+6.4)

The computer evaluates the denominator as:

x=3/(int)(10.9)

The denominator is then converted to an integer. So, we have:

x = 3/10;

3/10 = 0.3 but

Recall that: x will only hold non decimal numbers.

So:

x = 0;