You have a passage of text that needs to be typed out, but some of the letter keys on your keyboard are broken! You're given an array letters representing the working letter keys, as well as a string text, and your task is to determine how many of the words from text can be typed using the broken keyboard. It is guaranteed that all of the non-letter keys are working (including all punctuation and special characters).

def broken_keyboard(text, characters):

   my_keys = [i.lower() for i in characters]

   count = 0

   words = list(text.split(" "))

   for word in words:

       word=word.lower()

       for char in word:

           if(char in my_keys or is not char.isalpha()):    

               count += 1  

   return count

Explanation:

The python function "broken_keyboard" returns the count of keys that can be used in the broken keyboard. It accepts two arguments, the strings of words and a list of character strings of letters that can be used in the keys.

ιт ιѕ ωнєи ѕσмєσиє ρυтѕ ιи α ¢σ∂є σя ѕσмєтнιиg тнαт вяιиgѕ α νιяυѕ, σя мєѕѕєѕ уσυя gαмє υρ, σя αℓℓσωѕ тнєм тσ ¢нєαт.

αи∂ уєѕ ι нανє вєєи нα¢кє∂ вєfσяє(ιт αιит fυи)

нσρє ι ¢συℓ∂ нєℓρ уσυ.

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