Write a program that declares an array named myArray with 8 components of the type int. Initialize the array to 8 values that the user inputs (remember to prompt the user). Finally, pass the array as a parameter to a new function called filterEvens. This new function will display all of the even numbers in the array.

#include <iostream>

using namespace std;

void filterEvens(int myArray[]) {

   for (int i = 0; i < 8; ++i) {

     if(myArray[i]%2==0){

         cout<<myArray[i]<<" ";

     }

  }

}

int main(){

   int myArray[8];

   for(int i =0;i<8;i++){

       cin>>myArray[i];

   }

   filterEvens(myArray);

   return 0;

}

Explanation:

The solution is provided in C++

#include <iostream>

using namespace std;

The function filerEvens is defined here

void filterEvens(int myArray[]) {

This iterates through the elements of the array

   for (int i = 0; i < 8; ++i) {

This checks if current element is an even number

     if(myArray[i]%2==0){

If yes, this prints the array element

         cout<<myArray[i]<<" ";

     }

  }

}

The main begins here

int main(){

This declares an integer array of 8 elements

   int myArray[8];

The following iteration allows input into the array

   for(int i =0;i<8;i++){

       cin>>myArray[i];

   }

This calls the defined function filter Evens

   filterEvens(myArray);

   return 0;

}