What is a font's baseline? A

The imaginary line on which most letters "sit" unless part of the letter extends lower, like "g" or "j."
B

The imaginary line below which the font cannot extend, making it the lower limit for a line of text.
C

The center line for the font, which serves as a reference point.
D

The line at the top of the font's characters, under which all characters fit.

You need a reliable network for about twenty-five computers that will be distributed across a large building. it is important that the network be relatively cheap. which topology should you use?

Jane’s team is using the v-shaped model for their project. during the high-level design phase of the project, testers perform integration testing. what is the purpose of an integration test plan in the v-model of development? a. checks if the team has gathered all the requirements b. checks how the product interacts with external systems c. checks the flow of data in internal modules d. checks how the product works from the client side

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }