You will create a program that will take in the values for two points (x1 , x2) and (y1, y2) to find the slope of a line that contains those two points. I have provided the pseudocode for you below. All you need to do is translate the pseudocode to a Python program that will run and output the correct slope.

You can test your program by entering the following two point values: (x1 , y1) –> (32, 22) and (x2 , y2) –> (53, 36). Your slope should be 2/3.

PROCEDURE getCoordinates ()
{
<< global variables predefined in starter code >>

DISPLAY (What is the value of x1?)

x1 ← INPUT()

DISPLAY (What is the value of y1?)

y1 ← INPUT()

DISPLAY (What is the value of x2?)

x2 ← INPUT()

DISPLAY (What is the value of y2?)

y2 ← INPUT()

}

PROCEDURE getSlope()

{

<< global variables predefined in starter code >>

numerator ← y2 - y1

denominator ← x2 - x1

getHighestMultiple()

numerator ← numerator / highestMultiple

denominator ← denominator / highestMultiple

DISPLAY(“Slope is ” + numerator + “/” + denominator)

}

PROCEDURE getHighestMultiple()

{

<< global variables predefined in starter code >>

temp ← numerator

while (temp > 1)

{

IF((numerator MOD temp == 0) and (denominator MOD temp == 0))

{

highestMultiple ← temp

}

temp ← temp - 1

}

}

getCoordinates();
getSlope();