Computers and Technology
Computers and Technology, 08.12.2020 15:40, jdiddy25

What are SOLID principles in programming?

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Computers and Technology, 22.06.2019 18:00, alexj29227405
Write a method named addall that could be placed inside the hashintset class. this method accepts another hashintset as a parameter and adds all elements from that set into the current set, if they are not already present. for example, if a set s1 contains [1, 2, 3] and another set s2 contains [1, 7, 3, 9], the call of s1.addall(s2); would change s1 to store [1, 2, 3, 7, 9] in some order. you are allowed to call methods on your set and/or the other set. do not modify the set passed in. this method should run in o(n) time where n is the number of elements in the parameter set passed in.
Answers: 2
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Computers and Technology, 22.06.2019 19:20, ChaosMind
Write a program that reads a file consisting of students’ test scores in the range 0–200. it should then determine the number of students having scores in each of the following ranges: 0–24, 25–49, 50–74, 75–99, 100–124, 125–149, 150–174, and 175–200. output the score ranges and the number of students. (run your program with the following input data: 76, 89, 150, 135, 200, 76, 12, 100, 150, 28, 178, 189, 167, 200, 175, 150, 87, 99, 129, 149, 176, 200, 87, 35, 157, 189.)
Answers: 3
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Computers and Technology, 22.06.2019 19:20, mayaparness
Write a program that prompts the user to input a string. the program then uses the function substr to remove all the vowels from the string. for example, if str = "there", then after removing all the vowels, str = "thr". after removing all the vowels, output the string. your program must contain a function to remove all the vowels and a function to determine whether a character is a vowel.
Answers: 2
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Computers and Technology, 24.06.2019 00:40, sierravick123owr441
Use a software program or a graphing utility with matrix capabilities to solve the system of linear equations using an inverse matrix. x1 + 2x2 βˆ’ x3 + 3x4 βˆ’ x5 = 6 x1 βˆ’ 3x2 + x3 + 2x4 βˆ’ x5 = βˆ’6 2x1 + x2 + x3 βˆ’ 3x4 + x5 = 3 x1 βˆ’ x2 + 2x3 + x4 βˆ’ x5 = βˆ’3 2x1 + x2 βˆ’ x3 + 2x4 + x5 = 5
Answers: 3
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