Write a program that reads a list of integers, and outputs the two smallest integers in the list, in ascending order. The input begins with an integer indicating the number of integers that follow. You can assume that the list will have at least 2 integers and fewer than 20 integers. Ex: If the input is: 5 10 5 3 21 2 the output is: 2 3 To achieve the above, first read the integers into an array. Hint: Make sure to initialize the second smallest and smallest integers properly.

Following are the code to this question:

import java.util.*;//import package

public class Main //defining a Main class  

{

   public static void main(String[] args)//defining a main method  

   {

       Scanner oxc = new Scanner(System.in);//defining main method  

       int n,m1,m2,num,t,i;//defining integer variable

       n= oxc.nextInt();//input value from user end  

       m1 = oxc.nextInt(); //input value from user end

       m2 = oxc.nextInt(); //input value from user end

       if (m1 > m2)//defining if block that check m1 greater then m2  

       {

           //swapping the value

           t= m1;

           m1 = m2;

           m2 = t;

       }

       for (i=2;i<n;i++)//defining for loop that check the smallest value    

       {

           num = oxc.nextInt();//input value from user end

           if (num < m1) //defining if block that check num lessthan m1

           {

               m2 = m1;//store m1 value into m2  

               m1 = num;//store num value into m1

           }

           else if (num<m2)//defining else if block that check num lessthan m2

           {

               m2 = num;//store m2 value in num

           }

       }

       System.out.println(m1 + " " + m2);//print value

   }

}

Output:

5

10

5

3

21

2

2 3

Explanation:

In the above-given code, inside the main class the main method is declared, in method 6 integer variable "n,m1,m2, num,t, and i" is declared, and in the "n, m1, m2, and num" is used for input the value from the user end.

that would be my answer.

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