Given the IPv4 address, 200.245.10.150/28, how many subnets are possible and how many hosts can be supported by each subnet? a. 228 = 268 subnets, 24 -2 = 14 hosts per subnetwork
b. 24 = 16 subnets, 228 - 2 = 268E6 hosts per subnetwork
c. 24 - 2 = 14 subnets, 24 = 16 hosts per subnetwork
d. 24 = 16 subnets, 24 - 2 = 14 hosts per subnetwork

d. 24 = 16 subnets, 24 - 2 = 14 hosts per subnetwork

Explanation:

When four bits are borrowed from the fourth octet of class C IP address 200.245.10.150, the IP address is subnetted to 16 subnets, where the number of subnets is equal to two raised to the number of borrowed bits (ie, 2^ number of borrowed bits), and 14 assignable host IP address gotten from the formula;

  = 2^(number of host bits in the fourth octet) - 2

  = (2^4) - 2

  = 16 - 2 = 14 host addresses

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