Write a loop that sets each vector element to the sum of itself and the next element, except for the last element which stays the same. Be careful not to index beyond the last element. Ex:Initial scores: 10, 20, 30, 40Scores after the loop: 30, 50, 70, 40The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same. Sample program:#include #include using namespace std;int main() { const int SCORES_SIZE = 4; vector bonusScores(SCORES_SIZE); int i = 0; bonusScores. at(0) = 10; bonusScores. at(1) = 20; bonusScores. at(2) = 30; bonusScores. at(3) = 40; for (i = 0; i < SCORES_SIZE; ++i) { cout << bonusScores. at(i) << " "; } cout << endl; return 0;}

Add the following lines of code to the already existing code segment

for (i = 0; i < SCORES_SIZE-1; ++i) {

       bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);

 }

Explanation:

To do the task in the question, we have to iterate through the vector from the first element i.e. element at index 0 to the second to the last element; i.e. element at last index - 1

We then add each element in this iteration with the next.

This iterates through the vector from 0 to SCORES_SIZE - 1

for (i = 0; i < SCORES_SIZE-1; ++i) {

This adds each vector element with the next

       bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);

 }

The above should be added before

for (i = 0; i < SCORES_SIZE; ++i) {

       cout << bonusScores.at(i) << " ";

}

Also, I've made other modifications to the program.

See attachment for complete source code

answer; i do believe the correct answer is ( retailing); good luck