Write a function named getResults that accepts radius of a sphere and returns the volume and surface area. Call this function with radius = 3.5 , and display results in one decimal format. volume = 4/3 * pi * r ^ 3
Surface Area = 4pi * r ^ 2

Python

def getResults():

   radius = float(input())

   pi = 3.1415

   volume = 4/3 * pi * radius ** 3

   surfaceArea = 4*pi * radius ** 2.0

   print (volume)

   print (surfaceArea)

getResults()

C#:

       public static void Main(string[] args)

       {

           getResults(Convert.ToDouble(Console.ReadLine()));  

       }

       public static double[] getResults(double radius)

       {

           double radiusObj = radius;

           double volume = 1.33333333333 * Math.PI * Math.Pow(radiusObj, 3);

           double surfaceArea = 4 * Math.PI * Math.Pow(radiusObj, 2) ;

           double[] surfaceAndVolume = { volume, surfaceArea };

           Console.WriteLine(volume.ToString());

           Console.WriteLine(surfaceArea.ToString());

           return surfaceAndVolume;

       }

Java:

public static void main(String[] args)

   {

       Scanner  scanner = new Scanner(System.in);

       getResults(scanner.nextDouble());

   }

   public static double[] getResults(double radius)

   {

       double radiusObj = radius;

       double volume = 1.33333333333 * Math.PI * Math.pow(radiusObj, 3);

       double surfaceArea = 4 * Math.PI * Math.pow(radiusObj, 2) ;

       double[] surfaceAndVolume = { volume, surfaceArea };

       System.out.println(volume);

       System.out.println(surfaceArea);

       return surfaceAndVolume;

   }

the answer is you.