In the program below, what is the scope of strFirst? def usernameMaker (strFirst, strLast):
return strFirst + strLast[0]

def passwordMaker (strA, numC):
if len(strA) > 4:
answer = dogName[0:3]
return answer + str(numC)
else:
return 'xk&' + str(numC)

options

the function usernameMaker

the function passwordMaker and the main part of the program that calls the function

the function usernameMaker and the main part of the program calling the program

the function passwordMaker

The scope of a variable is the area where the variable can be accessed.

The scope of strFirst is (a) the function usernameMaker

From the program, we have the following function header

def usernameMaker (strFirst, strLast):

The above header implies that:

strFirst is a local variable of the function usernameMaker

This means that, the scope of strFirst is limited to the function usernameMaker

Hence, the correct option is (a)

Read more about scope of variables at:

link

First, we have to understand what scope is. When variables are declared, they are only available in the code block they're declared in, unless they're global variables (this doesn't apply here).

strFirst is declared in usernameMaker and that is the only place it is available in.

it could be e. idk for sure

answer; i believe the correct answer is (expression); good luck