Computers and Technology, 04.11.2020 18:30, nekobaby75
For this project, you will use your knowledge of both symmetric and asymmetric encryptions methods, specifically AES and RSA Public-key/Private-key, to determine the contents of a secret message. Each of you has been issued a specific dataset (please see the dataset assignment matrix to identify your dataset). Each dataset contains:
Answers: 2
Computers and Technology, 22.06.2019 19:20, bob4059
1)consider the following code snippet: #ifndef book_h#define book_hconst double max_cost = 1000.0; class book{public: book(); book(double new_cost); void set_cost(double new_cost); double get_cost() const; private: double cost; }; double calculate_terms(book bk); #endifwhich of the following is correct? a)the header file is correct as given. b)the definition of max_cost should be removed since header files should not contain constants. c)the definition of book should be removed since header files should not contain class definitions. d)the body of the calculate_terms function should be added to the header file.
Answers: 1
Computers and Technology, 23.06.2019 19:00, brittneyrenae7338
This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }
Answers: 1
Computers and Technology, 25.06.2019 07:50, hayleneolide
Identify an advantage of centralized processing
Answers: 1
For this project, you will use your knowledge of both symmetric and asymmetric encryptions methods,...
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