Write a program with class name Digits that prompts the user to input a positive integer and then outputs the number reversed and the sum of the digits. For example, if the user enters the number 3456, then your program should output 6543 and the sum as 18. Use a while loop. Hint: use the mod operator and 10 as divider to find the right most digit and to update the value of controlling expression

Written in Python:

inputnum = int(input("User Input: "))

outputnum = 0

total = 0

while(inputnum>0):

     remainder = inputnum % 10

     outputnum = (outputnum * 10) + remainder

     inputnum = inputnum//10

     total = total + remainder

print("Reverse: "+str(outputnum))

print("Total: "+str(total))

Explanation:

This prompts user for input

inputnum = int(input("User Input: "))

This initializes the reverse number to 0

outputnum = 0

This initializes total to 0; i.e. sum of each digit

total = 0

The following iteration gets the reverse of user input

while(inputnum>0):

     remainder = inputnum % 10

     outputnum = (outputnum * 10) + remainder

     inputnum = inputnum//10

     This adds each digit of user input

     total = total + remainder

This prints the reversed number

print("Reverse: "+str(outputnum))

This prints the sum of each digit

print("Total: "+str(total))

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