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Working on this program in python 3.7: a year in the modern gregorian calendar consists of 365 days. in reality, the earth takes longer to rotate around the sun. to account for the difference in time, every 4 years, a leap year takes place. a leap year is when a year has 366 days: an extra day, february 29th. the requirements for a given year to be a leap year are: 1) the year must be divisible by 42) if the year is a century year (1700, 1800, the year must be evenly divisible by 400some example leap years are 1600, 1712, and 2016.write a program that takes in a year and determines whether that year is a leap year. ex: if the input is 1712, the output is: 1712 is a leap year. ex: if the input is 1913, the output is: 1913 is not a leap year. your program must define and call the function isleapyear(useryear). the function should return true if the input year is a leap year and false otherwise.

The camera still is bad even with the new iphone xr and especially in low light it is even worst because you can see the pixels more if its in low light. if all you apple customers want apple to fix this then lets fill there feedback with complaints about the can apple do to fix this issue?

3. what is the output of the following statements? temporary object1; temporary object2("rectangle", 8.5, 5); temporary object3("circle", 6, 0); temporary object4("cylinder", 6, 3.5); cout < < fixed < < showpoint < < setprecision(2); object1.print(); object2.print(); object3.print(); object4.print(); object1.set("sphere", 4.5, 0); object1.print();