Consider the following hypotheses: If it does not rain or if it is not foggy, then the sailing race will be held and the lifesaving demonstration will go on If the sailing race is held, then the trophy will be awarded The trophy was not awarded Arrange the steps in the correct order to show that these hypotheses imply the conclusion "It rained," using rules of interference.
Rank the options below.
1. We get the conclusion "it rained" from the given hypotheses.
2. Taking the contrapositive of (﹁rv → (SA ), we get(s^ ) →すrv ﹁ s and ( s v (r ^ imply that s v l, using addition.
3. The givenpremises are (﹁rv → (SA ) , s → t, and t
4. By modus ponens, ( s v (r^ ή and s v , imply r^ f and r^ fimplies r using simplification.
5. Let r be the proposition "t rains," let fbe the proposition "It is foggy," let s be the proposition "The sailing race will be held," let /b proposition "The lifesaving demonstration will go on," and let t be the proposition "The trophy will be awarded."
6. Applying De Morgan's law on ר(SA →ヤrv ﹁5, we obtain (าร ν רり→ (ГлかUsing and s → t, we get ﹁s is true

What is the most popular genre of video games?

The processing of data in a computer involves the interplay between its various hardware components.

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words. size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words. size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }