Computers and Technology, 12.08.2020 06:01, alondraalfaro06
How can I reduce the number of loops, possibly into one loop on my solution below? The logic is right and it passes all my test cases but it looks a bit verbose. const hourglassSum = (arr) => { let count = 1; const hourglass = []; const flatglass = []; let idx = 0; do { const idx2 = idx + 1; const idx3 = idx + 2; hourglass. push([ [arr[0][idx], arr[0][idx2], arr[0][idx3]], [0, arr[1][idx2], 0], [arr[2][idx], arr[2][idx2], arr[2][idx3]], ]); idx += 1; count += 1; } while (count 4 && count 8 && count 12 && count { const flattened = [].concat(...innerglass); const arrSum = flattened. reduce((a, b) => a + b, 0); flatglass. push(arrSum); }); return Math. max(...flatglass); };
Answers: 1
Computers and Technology, 23.06.2019 04:00, terrell31
Write a method that takes in an array of point2d objects, and then analyzes the dataset to find points that are close together. be sure to review the point2d api. in your method, if the distance between any pair of points is less than 10, display the distance and the (x, y)s of each point. for example, "the distance between (3,5) and (8,9) is 6.40312." the complete api for the point2d adt may be viewed at ~pf/sedgewick-wayne/algs4/documenta tion/point2d. html (links to an external site.)links to an external site.. try to write your program directly from the api - do not review the adt's source code.
Answers: 1
How can I reduce the number of loops, possibly into one loop on my solution below? The logic is righ...
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