Computers and Technology

Partial Credit 1: How many bits are in the tag field? (i. e. the tag itself not including any counter bits) Solution: Here, 2^w=1  w=0. 2^m=1  m=0. 2^a=16  a=4. t=a-m-w=4-0-0=4.

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Partial Credit 1: How many bits are in the tag field? (i. e. the tag itself not including any counte...

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