Volume of Pyramid = A*h/3 where A is the area of the base of the pyramid and h is the height of the pyramid. Write a C++ program that asks the user to enter the necessary information about the pyramid (note that the user would not know the area of the base of the pyramid, you need to ask them for the length of one of the sides of the base and then calculate the area of the base). Using the information the user input, calculate the volume of the pyramid. Next display the results (rounded to two decimal places). Example Output (output will change depending on user input): The area of the base of the pyramid is: 25.00 The height of the pyramid is: 5.00 The volume of the pyramid is: 41.67 *Pseudocode IS required for this program and is worth 1 point. The program IS auto-graded.

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

   double side, height;

   cout<<"Enter the length of one of the sides of the base: ";

   cin>>side;

   cout<<"Enter the height: ";

   cin>>height;

   double area = side * side;

   double volume = area * height / 3;

   cout<<"The area of the base of the pyramid is: "<<area<<endl;

   cout<<"The height of the pyramid is: "<<height<<endl;

   cout<<"The volume of the pyramid is: "<<fixed<<setprecision(2)<<volume<<endl;

   return 0;

}

Pseudocode:

Declare side, height

Get side

Get height

Set area = side * side

Set volume = area * height / 3

Print area

Print height

Print volume

Explanation:

Include <iomanip> to have two decimal places

Declare the side and height

Ask the user to enter side and height

Calculate the base area, multiply side by side

Calculate the volume using the given formula

Print area, height and volume (use fixed and setprecision(2) to have two decimal places)

answer; ///i believe that neither technician a or technician b are correct answer(both are false);