Which of the following patterns should be used for the delimiter to read one character at a time using a Scanner object's next method? Scanner in = new Scanner(. . .); in. useDelimiter("[^0-9]+"); Scanner in = new Scanner(. . .); in. useDelimiter(""); Scanner in = new Scanner(. . .); in. useDelimiter("[^A-Za-z]+"); Scanner in = new Scanner(. . .); in. useDelimiter("[A-Za-z]+");

The method to this question can be defined as follows:

Scanner in = new Scanner(. . .);

in.useDelimiter("");

Explanation:

Following are the code to the question:

import java.util.*;    //import package for user input

public class Main //defining class Main

{    

public static void main(String ax[])//defining the main method

{    

   Scanner in = new Scanner("Database");//crearing Scanner class object that pass value in its parameter  

   in.useDelimiter("");  //using useDelimiter

   System.out.println(in.next()); //use print method to print single character value

}    

}    

Output:

D

Code explanation:

some have built technology like spoofed call blockers into their networks, so there's nothing you would even have to install.

this happens because the number is known for scamming, they don't want it to me known as "scam likely." perhaps it's just a telemarketer. maybe it's an identity thief. it might even be a scam artist.  

either way, "scam likely" is probably not an old friend whose number you forgot that you saved. it's your wireless carrier's way of letting you know: answer at your own risk.

explanation:

to combat the seemingly rising epidemic of spam callers in the u.s., the nation's four major wireless carriers have been trying out new methods to reduce the number of unsolicited calls americans receive each day.

some have built technology like spoofed call blockers into their networks, so there's nothing you would even have to install.

hope this . mark me brainliest.

sory but complete the question