What is the channel capacity for a teleprinter channel with a 300 Hz bandwidth and a signal-to-noise ratio of 30dB, where the noise is white thermal noise?

The answer is 2988 bits per seconds

Explanation:

Solution

Given that:

Bandwidth (B) = 300Hz

Signal to noise ratio (SNR) = 30dB

Now let C = channel capacity

Using  Deubel formula we have the following:

SNR db = 10* log (SNR)

30 =10* log (SNR)

So,

SNR =log^⁻1 (3)

SNR = (10)^3

SNR = 1000

Thus SNR =1000

Now

Applying the Shannon's equation

C = B * log₂ ( 1 + SNR)

C = 300 * log₂ ( 1 + 1000)

C = 300 * log₂ (1001)

C = 300 * 9.96

C =2988

Hence the capacity of the channel for teleprinter channel is 2988 bits per second.

a.s= 230t– 110; 1500 lbc.t= 230s– 110; 1500 lbb.s= 230t+ 110; 1720 lbd.s= 199t– 110; 1280 lb