Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 2, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bagOunces followed by " seconds". End with a newline. Example output for ounces.1 #include 2 using namespace std; 34 void PrintPopcornTime (int bagOunces)5 6 Your solution goes here 10 int main) 7891011 PrintPopcornTime(7) 12 13 return 0 14

#include <iostream>

using namespace std;

void PrintPopcornTime (int bagOunces){

   if (bagOunces < 2){

       cout << "Too small"<<endl;

   }

   else if (bagOunces > 10){

       cout << "Too large"<<endl;

   }

   else{

       cout << bagOunces*6 <<" seconds"<<endl;

   }

}

int main(){

   PrintPopcornTime(7);

   return 0;

}

Explanation:

Create a function called PrintPopcornTime that takes one parameter, bagOunces

Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".

Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.